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प्रश्न
In right angled ΔTSU, TS = 5, ∠S = 90°, SU = 12 then find sin T, cos T, tan T. Similarly find sin U, cos U, tan U.
उत्तर
In right ∆TSU,
TU2 = SU2 + TS2 ...(Pythagoras theorem)
⇒ TU2 = 122 + 52
⇒ TU2 = 144 + 25
⇒ TU2 = 169
⇒ TU = 13
Now,
sin T = `("∠T" "opposite side")/("Hypotenuse") = "SU"/"TU" = 12/13`
cos T = `("∠T" "adjacent side")/("Hypotenuse") = "TS"/"TU" = 5/13`
tan T = `("∠T" "opposite side")/("∠T" "adjacent side") = "SU"/"TS" = 12/5`
Also,
sin U = `("∠U" "opposite side")/("Hypotenuse") = "TS"/"TU" = 5/13`
cos U = `("∠U" "adjacent side")/("Hypotenuse") = "SU"/"TU" = 12/13`
tan U = `("∠U" "opposite side")/("∠U" "adjacent side") = "TS"/"SU" = 5/12`
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