Advertisements
Chapters
![Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 - Circle Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 - Circle - Shaalaa.com](/images/geometry-mathematics-2-english-9-standard-maharashtra-state-board_6:0e8db292b5c64d6e8d65b3ca4a58b2d7.jpg)
Advertisements
Solutions for Chapter 6: Circle
Below listed, you can find solutions for Chapter 6 of Maharashtra State Board Balbharati for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 6 Circle Practice Set 6.1 [Page 79]
Distance of chord AB from the centre of a circle is 8 cm. Length of the chord AB is 12 cm. Find the diameter of the circle.
Diameter of a circle is 26 cm and length of a chord of the circle is 24 cm. Find the distance of the chord from the centre.
Radius of a circle is 34 cm and the distance of the chord from the centre is 30 cm, find the length of the chord.
Radius of a circle with centre O is 41 units. Length of a chord PQ is 80 units, find the distance of the chord from the centre of the circle.
In the given figure, centre of two circles is O. Chord AB of bigger circle intersects the smaller circle in points P and Q. Show that AP = BQ.
Prove that, if a diameter of a circle bisects two chords of the circle then those two chords are parallel to each other.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 6 Circle Practice Set 6.2 [Page 82]
Radius of circle is 10 cm. There are two chords of length 16 cm each. What will be the distance of these chords from the centre of the circle?
In a circle with radius 13 cm, two equal chords are at a distance of 5 cm from the centre. Find the lengths of the chords.
Seg PM and seg PN are congruent chords of a circle with centre C. Show that the ray PC is the bisector of ∠NPM.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 6 Circle Practice Set 6.3 [Page 86]
Construct ΔABC such that ∠B = 100°, BC = 6.4 cm, ∠C = 50° and construct its incircle.
Construct ΔPQR such that ∠P = 70°, ∠R = 50°, QR = 7.3 cm and constructs its circumcircle.
Construct ΔXYZ such that XY = 6.7 cm, YZ = 5.8 cm, XZ = 6.9 cm and constructs its incircle.
In ΔLMN, LM = 7.2 cm, ∠M = 105°, MN = 6.4 cm, then draw ΔLMN and construct its circumcircle.
Construct ΔDEF such that DE = EF = 6 cm, ∠F = 45° and constructs its circumcircle.
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board 6 Circle Problem Set 6 [Pages 86 - 87]
Choose correct alternative answer and fill in the blanks.
Radius of a circle is 10 cm and distance of a chord from the centre is 6 cm. Hence the length of the chord is ______.
16 cm
8 cm
12 cm
32 cm
The point of concurrence of all angle bisectors of a triangle is called the ______.
Centroid
Circumcentre
Incentre
Orthocentre
The circle which passes through all the vertices of a triangle is called ______.
Circumcircle
Incircle
Congruent circle
Concentric circle
Length of a chord of a circle is 24 cm. If distance of the chord from the centre is 5 cm, then the radius of that circle is ______.
12 cm
13 cm
14 cm
15 cm
The length of the longest chord of the circle with radius 2.9 cm is ______.
3.5 cm
7 cm
10 cm
5.8 cm
Radius of a circle with centre O is 4 cm. If l(OP) = 4.2 cm, say where point P will lie.
On the centre
Inside the circle
Outside the circle
On the circle
The lengths of parallel chords which are on opposite sides of the centre of a circle are 6 cm and 8 cm. If radius of the circle is 5 cm, then the distance between these chords is ______.
2 cm
1 cm
8 cm
7 cm
Construct incircle and circumcircle of an equilateral Δ DSP with side 7.5 cm. Measure the radii of both the circles and find the ratio of radius of circumcircle to the radius of incircle.
Construct ΔNTS where NT = 5.7 cm, TS = 7.5 cm and ∠NTS = 110° and draw incircle and circumcircle of it.
In the given figure, C is the centre of the circle. seg QT is a diameter CT = 13, CP = 5, find the length of chord RS.
In the given figure, P is the centre of the circle. chord AB and chord CD intersect on the diameter at the point E. If ∠AEP ≅ ∠DEP then prove that AB = CD.
In the given figure, CD is a diameter of the circle with centre O. Diameter CD is perpendicular to chord AB at point E. Show that ΔABC is an isosceles triangle.
Solutions for 6: Circle
![Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 - Circle Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 - Circle - Shaalaa.com](/images/geometry-mathematics-2-english-9-standard-maharashtra-state-board_6:0e8db292b5c64d6e8d65b3ca4a58b2d7.jpg)
Balbharati solutions for Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 - Circle
Shaalaa.com has the Maharashtra State Board Mathematics Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Balbharati solutions for Mathematics Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board Maharashtra State Board 6 (Circle) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Balbharati textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board chapter 6 Circle are Concept of Circle, Properties of Chord, Construction of the Incircle of a Triangle., Circumcentre of a Triangle, Theorem: a Perpendicular Drawn from the Centre of a Circle on Its Chord Bisects the Chord., Theorem : The Segment Joining the Centre of a Circle and the Midpoint of Its Chord is Perpendicular to the Chord., Relation Between Congruent Chords of a Circle and Their Distances from the Centre, Properties of Congruent Chords, Theorem: Equal chords of a circle are equidistant from the centre., Theorem : The Chords of a Circle Which Are Equidistant from the Centre Are Equal., Incircle of a Triangle, Construction of the Circumcircle of a Triangle.
Using Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board solutions Circle exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board students prefer Balbharati Textbook Solutions to score more in exams.
Get the free view of Chapter 6, Circle Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board additional questions for Mathematics Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board Maharashtra State Board, and you can use Shaalaa.com to keep it handy for your exam preparation.