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Question
450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited. Caclulate the composition of resulting mixture.
\[\ce{2NO + O2 → 2NO2}\]
Solution
\[\ce{2NO + O2 → 2NO2}\]
2 V 1 V 2 V
From equation, 1V of O2 reacts with = 2 V of NO
200cm3 oxygen will react with = 200 × 2 = 400 cm3 NO
2 vols. of NO produces = 2 vols. of NO2
∴ 400 cm3 of NO produces NO2 = 400 cm3
∴ Vol. of NO left unused = 450 − 400
= 50 cm3
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