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Question
A bag contains 10 red balls, 16 white balls and 8 green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be neither red nor green?
Solution
Total number of possible outcomes = 10 + 16 + 8 = 34 balls
n(S) = 34
Favorable outcomes for neither a red nor a green ball = favourable outcomes for white ball
Number of favorable outcomes for white ball = 16 = n(E)
Probability for not drawing a red or green ball = `(n(E))/(n(S)) = 16/34 = 8/17`
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