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Question
A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is Not red
Solution
Total number of possible outcomes = 12 {3 red balls, 5 black balls & 4 white balls}
E ⟶ event of getting red
No. of favourable outcomes = 3 {3 black balls}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) =3/12 =1/4
`barE` ⟶ event of not getting red.
P`(barE)` = 1 – P(E)
= 1–(1/4)
=3/4
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