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Question
A bag contains 5 pink, 8 blue and 7 yellow balls. One ball is drawn at random from the bag. What is the probability of getting neither a blue nor a pink ball?
Options
`1/4`
`2/5`
`7/20`
`13/20`
Solution
`bb(7/20)`
Explanation:
Number of pink balls = 5
Number of blue balls = 8
Number of yellow balls = 7
Total number of balls = 5 + 8 + 7 = 20
Probability of getting neither a blue nor a pink ball = Probability of getting a yellow ball
= `"Number of yellow balls"/"Total number of balls"`
= `7/20`
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