Advertisements
Advertisements
Question
In the given figure, DE || BC. If AD = 3 cm, AB = 7 cm and EC = 3 cm, then the length of AE is ______.
Options
2 cm
2.25 cm
3.5 cm
4 cm
Solution
In the given figure, DE || BC. If AD = 3 cm, AB = 7 cm and EC = 3 cm, then the length of AE is 2.25 cm.
Explanation:
Given, AD = 3 cm, AB = 7 cm, EC = 3 cm.
Let AE = x cm
∴ AC = AE + EC = x + 3 cm
As we know that
`(AD)/(AB) = (AE)/(AC)`
`\implies 3/7 = x/(x + 3)`
`\implies` 3(x + 3) = 7x
`\implies` 3x + 9 = 7x
`\implies` 7x – 3x = 9
`\implies` 4x = 9
`\implies` x = `9/4` = 2.25 cm
∴ length of AE = 2.25 cm
APPEARS IN
RELATED QUESTIONS
In a ΔABC, D and E are points on AB and AC respectively such that DE || BC. If AD = 2.4cm, AE = 3.2 cm, DE = 2cm and BC = 5 cm, find BD and CE.
Find the height of an equilateral triangle of side 12cm.
In ΔABC, D is the midpoint of BC and AE⊥BC. If AC>AB, show that `AB^2= AD^2+1/4 BC^2 −BC.DE `
Find the length of each side of a rhombus whose diagonals are 24cm and 10cm long.
In the given figure, D is the midpoint of side BC and AE⊥BC. If BC = a, AC = b, AB = c, AD = p and AE = h, prove that
(i)`B^2=p^2+ax+a^2/x`
(ii)` c^2=p^2-ax+a^2/x`
(iii) `b^2+c^2=2p^2+a^2/2`
(iv)`b^2-c^2=2ax`
State the midpoint theorem
In triangle BMP and CNR it is given that PB= 5 cm, MP = 6cm BM = 9 cm and NR = 9cm. If ΔBMP∼ ΔCNR then find the perimeter of ΔCNR
Each of the equal sides of an isosceles triangle is 25 cm. Find the length of its altitude if the base is 14 cm.
In figure, PA, QB, RC and SD are all perpendiculars to a line l, AB = 6 cm, BC = 9 cm, CD = 12 cm and SP = 36 cm. Find PQ, QR and RS.
O is the point of intersection of the diagonals AC and BD of a trapezium ABCD with AB || DC. Through O, a line segment PQ is drawn parallel to AB meeting AD in P and BC in Q. Prove that PO = QO.