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Question
A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin will not be a Rs 2 coin?
Solution
Total number of coins = 20 + 50 + 30 = 100
Total possible outcomes = 100 = n(S)
Number of favorable outcomes for not a Rs 2 coins = number of favorable outcomes for Re 1 or Rs 5 coins = 30 + 20 = 50 = n(E)
Probability (not Rs 2 coin) = `(n(E))/(n(S)) = 50/100 = 1/2`
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