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A box contains 5 red, 8 blue and 3 green pens. Rutuja wants to pick a pen at random. What is the probability that the pen is blue? - Algebra

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Question

A box contains 5 red, 8 blue and 3 green pens. Rutuja wants to pick a pen at random. What is the probability that the pen is blue?

Sum

Solution

Let 5 red pens be R1, R2, R3, R4, R5;
8 blue pens be B1, B2, B3, B4, B5, B6, B7, B8 and
3 green pens be G1, G2, G3.

Sample space,

S = {R1, R2, R3, R4, R5, B1, B2, B3, B4, B5, B6, B7, B8, G1, G2, G3}

∴ n(S) = 16

Let A be the event Rutuja picks a blue pen.

∴ A = {B1, B2, B3, B4, B5, B6, B7, B8}

∴ n(A) = 8

∴ P(A) = `("n"("A"))/("n"("S")) = 8/16`

∴ P(A) = `1/2`

∴ The probability that Rutuja picks a blue pen is `1/2`.

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Chapter 5: Probability - Problem Set 5 [Page 127]

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