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Question
If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is
Options
\[\frac{3}{10}\]
\[\frac{29}{100}\]
\[\frac{1}{3}\]
\[\frac{7}{25}\]
Solution
A two digit number is chosen at random to find Probability that the number chosen is a multiple of 3
Total two digit numbers are 90
Two digit Numbers multiple of 3 are 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99
Hence total two digit numbers multiple of 3 are 30
We know that Probability = `"Number of favourable event"/"Total number of event"`
Hence the probability that the number chosen is a multiple of 3 is equal to `30/90=1/3`
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