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Question
Two different dice are rolled together. Find the probability of getting the sum of numbers on two dice to be 5.
Solution
-
1
2
3
4
5
6
1
(1, 1)
(1, 2)
(1, 3)
(1, 4)
(1, 5)
(1, 6)
2
(2, 1)
(2, 2)
(2, 3)
(2, 4)
(2, 5)
(2, 6)
3
(3, 1)
(3, 2)
(3, 3)
(3, 4)
(3, 5)
(3, 6)
4
(4, 1)
(4, 2)
(4, 3)
(4, 4)
(4, 5)
(4, 6)
5
(5, 1)
(5, 2)
(5, 3)
(5, 4)
(5, 5)
(5, 6)
6
(6, 1)
(6, 2)
(6, 3)
(6, 4)
(6, 5)
(6, 6)
∴ Total number of possible outcomes = 36
We know
Probability of an event= `"Favourable number of outcomes"/"Total number of outcomes"`
The outcomes favourable to the event 'the sum of the numbers on two dice to be 5' denoted by E are (1, 4), (2, 3), (4, 1) and (3, 2).
Total number of favourable outcomes = 4
`:.P(E)=4/36=1/9`
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