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Question
A balloon vendor has 2 red, 3 blue and 4 green balloons. He wants to choose one of them at random to give it to Pranali. What is the probability of the event that Pranali gets, a red balloon
Solution 1
Given: Number of red balloon = 2
Number of blue balloon = 3
Number of green balloon = 4
Let S be the sample space.
∴ n(S) = Number of red balloon + Number of blue balloon + Number of green balloon
= 2 + 3 + 4
= 9
Let A be the event of getting a red balloon.
Given: n(A) = 2
∴ `P(A) = (n(A))/(n(S))`
= `2/9`
Hence, the probability of the event that Pranali gets a red balloon is `2/9`.
Solution 2
Let the 2 red balloons be R1, R2,
3 blue balloons be B1, B2, B3 and
4 green balloons be G1, G2, G3, G4.
∴ Sample space,
S = {R1, R2, B1, B2, B3, G1, G2, G3, G4}
∴ n(S) = 9
Let A be the event that Pranali gets a red balloon.
∴ A = {R1, R2}
∴ n(A) = 2
∴ P(A) = `("n"("A"))/("n"("S"))`
∴ P(A) = `2/9`
∴ The probability that Pranali gets a red balloon is `2/9`
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