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Question
The probability of throwing a number greater than 2 with a fair dice is
Options
\[\frac{3}{5}\]
\[\frac{2}{5}\]
\[\frac{2}{3}\]
\[\frac{1}{3}\]
Solution
dice is thrown once
TO FIND: Probability of getting a number greater than 2.
Total number on a dice is 6.
Number greater than 2 is 3, 4, 5 and 6
Total number greater than 2 is 4
`"We know that PROBABILITY" = "Number of favourable event"/"Total number of event"`
Hence probability of getting a number greater than 2 is equal to `4/6=2/3`
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