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Question
A number is selected at random from the numbers 3, 5, 5, 7, 7, 7, 9, 9, 9, 9 The probability that the selected number is their average is
Options
\[\frac{1}{10}\]
\[\frac{3}{10}\]
\[\frac{7}{10}\]
\[\frac{9}{10}\]
Solution
GIVEN: A number is selected from the numbers 3,5,5,7,7,7,9,9,9,9
TO FIND: Probability that the selected number is the average of the numbers Total numbers are 10
Average of numbers
`=(3+5+5+7+7+7+9+9+9+9)/10`
`=70/10`
`= 7`
Total numbers of numbers which are average of these numbers are 3
`"We know that PROBABILITY "= " Number of favourable event"/"Total number of event"`
Hence Probability that the selected number is the average of the numbers is `3/10`
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