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Question
Two dice are rolled together. Find the probability of getting such numbers on the two dice whose product is 12.
Solution
Number of all possible outcomes = 36
Let E be the event of getting all those numbers whose product is 12.
These numbers are (2, 6), (3, 4), (4, 3) and (6, 2).
∴ P(getting all those numbers whose product is 12) = P(E) =`"Number of outcome favourable to E"/"Number of all possible outcomes"`
`=4/36 = 1/9 `
Thus, the probability of getting all those numbers whose product is 12 is `1/9`
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