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Question
An integer is chosen at random between 1 and 100. Find the probability that it is
1) divisible by 8.
2) not divisible by 8.
Solution
S = {2, 3 ..., 99}
n(S) = 98
1) A: Getting an integer divisible by 8.
A = {8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96}
n(A) = 12
`P(A) = (n(A))/(n(s)) = 12/98 = 0.1224`
2) B: Getting an integer not divisible by 8
P(B) = 1 -">−- Probability of getting integer divisible by 8
P(B) = 1 -">−- P(A) = 1 - 0.1224 = 0.8756
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