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Question
In Q. No. 1, The probability that the digit is even is
Options
\[\frac{4}{9}\]
\[\frac{5}{9}\]
\[\frac{1}{9}\]
\[\frac{2}{3}\]
Solution
digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.
TO FIND: Probability of getting an even digit
Total number of digits is 9
Digits that are even number are 2, 4, 6, and 8
Total number of even digits is 4.
`"We know that PROBABILITY "= "Number of favourable event" /"Total number of event"`
Hence probability of getting an even digit is `4/9`
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