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Question
In the probability that the digit is a multiple of 3 is
Options
\[\frac{1}{3}\]
\[\frac{2}{3}\]
\[\frac{1}{9}\]
\[\frac{2}{9}\]
Solution
digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.
TO FIND: Probability of getting a multiple of 3
Total number of digits is 9
Digits that are multiple of 3 are 3, 6 and 9
Total digits that are multiple of 3 are 3
`"We know that PROBABILITY" =" Number of favourablr event"/"Total number of event"`
Hence probability of getting a multiple of 3 is `3/9=1/3`
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