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Question
If P(E) = 0.05, then P(not E) =
Options
−0.05
0.5
0.9
0.95
Solution
`P(E)=0.05`
TO FIND:` P(overline E)`
We know that sum of probability of occurrence of an event and probability of non occurrence of an event is 1. Therefore
`P(overline E)=1`
`0.05+p(overlineE)=1`
` p(overlineE)=1-0.05`
`P(overlineE)=0.95`
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