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Question
A die is thrown once. Find the probability of getting a number which (i) is a prime number (ii) lies between 2 and 6.
Solution
Total possible outcomes that occur after throwing a die once are 1,2,3,4,5,6
Number of possible outcomes = 6
(a) We need to find the probability of getting a prime number
Prime number is a number not divisible by any number except itself
Prime numbers on dice are 2,3 and 5.
Number of favourable outcomes =3
Probability of getting a prime number = `"Number of favourable outcomes"/"Total number of possible outcomes"`
Probability of getting a prime number=`3/6 = 1/2`
Therefore, probability of getting a prime number is `1/2`
(b) Probability of getting a number lying between 2 and 6
Number lying between 2 and 6 on a dice are 3,4 and 5.
Probability of getting a number lying between 2 and 6 =`3/6 = 1/2`
Therefore, Probability of getting a number lying between 2 and 6 is = `1/2`
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