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Question
In a single throw of a die, the probability of getting a multiple of 3 is
Options
\[\frac{1}{2}\]
\[\frac{1}{3}\]
\[\frac{1}{6}\]
\[\frac{2}{3}\]
Solution
A dice is thrown once
TO FIND: Probability of getting a multiple of 3.
Total number on a dice is 6.
Numbers which are on multiple of 3 are 3 and 6
Total number of numbers which are multiple of 3 is 2
`"We know that PROBABILITY" ="Number of favourable event"/"Total number of event"`
Hence probability of getting a number which are multiple of 3 is equal to `2/6=1/3`
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