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Question
A box contains 7 red balls, 8 green balls and 5 white balls. A ball is drawn at random from the box. Find the probability that the ball is neither red nor white.
Solution
Total number of balls in the box = 7 + 8 + 5 = 20 balls
Total possible outcomes = 20 = n(S)
Neither red ball nor white ball = green ball
Event of not drawing a red or white ball = E = number of green ball
n(E) = 8
Probability of drawing a white ball = `(n(E))/(n(S)) = 8/20 = 2/5`
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