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Question
A brown ring is formed in the ring test for \[\ce{NO3^{-}}\] ion. It is due to the formation of ______.
Options
\[\ce{[Fe(H2O)5 (NO)]^{2+}}\]
\[\ce{FeSO4.NO2}\]
\[\ce{[Fe(H2O)4(NO)2]^{2+}}\]
\[\ce{FeSO4.HNO3}\]
Solution
A brown ring is formed in the ring test for \[\ce{NO_{3}^{-}}\] ion. It is due to the formation of \[\ce{[Fe(H2O)5 (NO)]^{2+}}\].
Explanation:
When freshly prepared solution of \[\ce{FeSO4}\] is added in a solution containing \[\ce{NO3}\] ion, it leads to formation of a brown coloured complex. This is known as brown ring test of nitrate.
\[\ce{NO3^{-} + 3Fe^{2+} + 4H^{+} -> NO + 3Fe^{3+} + 2H2O}\]
\[\ce{[Fe(H2O)6]^{2+} + NO -> \underset{Brown ring}{[Fe(H2O)5(NO)]^{2+} + H2O}}\]
Hence, 2 moles of ammonia will produce 2 moles of NO.
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