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Question
A can do a work In 45 days. He works at it for 15 days and then, B alone finishes the remaining work in 24 days. Find the time taken to complete 80% of the work, if they work together
Solution
A complete the work in 45 days.
∴ A’s 1 day work = `1/45`
A's 15 days work = `15/45 = 1/3`
Remaining work = `1 - 1/3 = (3 - 1)/3 = 2/3`
B finishes `2/3` rd work in 24 days
B's 1 day work = `(2/3)/24`
= `2/(3 xx 24)`
= `1/36`
(A + B)'s 1 day work = `1/45 + 1/36`
| 9 | 45, 36 |
| 5, 4 |
= `(4 + 5)/180`
= `9/180`
= `1/20`
Let x days required
∴ `x/20 = 80/100`
⇒ x = `80/100 xx 20`
= 16 days
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