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Question
A certain nucleus X has a mass number 15 and atomic number 7. Find the number of neutrons. The nucleus X losses one α-particle and Express the change and write the symbol of the new nucleus.
Solution
Mass number = No. of protons + No. of neutrons
Atomic number = No. of protons
∴ No. of neutrons = Mass number - Atomic number
= 15 - 7 = 8
Element X can be written as \[\ce{_7^15X}\].
After the loss of one α-particle, the mass number is decreased by 4 and atomic number is decreased by 2. The element X changes to S.
\[\ce{_7^15X -> _5^11Z + _2^4He}\]
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