Advertisements
Advertisements
Question
A closed rectangular box is made of wood of 1.5 cm thickness. The exterior length and breadth are respectively 78 cm and 19 cm, and the capacity of the box is 15 cubic decimeters. Calculate the exterior height of the box.
Solution
Let exterior height is h cm.
Then interior dimensions are 78 - 3 = 75, 19 - 3 = 16 and h - 3 .....( subtract two thicknesses of wood ).
Interior volume = 75 x 16 x ( h - 3 ) which must = 15 cu dm
= 15000 cm3 ......(1 dm = 10cm, 1 cu dm = 103 cm3 ) .
15000 cm3 = 75 x 16 x ( h - 3 )
⇒ h - 3 = `15000/(75 xx 16)` = 12.5 cm
⇒ h = 15.5 cm.
APPEARS IN
RELATED QUESTIONS
A 4 cm cube is cut into 1 cm cubes. Calculate the total surface area of all the small cubes.
Find the surface area of a cuboid whose length = 10 cm, breadth = 12 cm, height = 14 cm.
Find the area of the cardboard required to make a closed box of length 25 cm, 0.5 m and height 15 cm.
A cuboid has total surface area of 50 m2 and lateral surface area is 30 m2. Find the area of its base.
The areas of three adjacent faces of a cuboid are x, y and z. If the volume is V, prove that V2 = xyz.
The external dimensions of a closed wooden box are 48 cm, 36 cm, 30 cm. The box is made of 1.5 cm thick wood. How many bricks of size 6 cm × 3 cm × 0.75 cm can be put in this box?
75 persons can sleep in a room 25 m by 9.6 m. If each person requires 16 m3 of the air; find the height of the room.
The length, breadth, and height of a cuboid are in the ratio 5 : 3: 2. If its volume is 240 cm3; find its dimensions. Also, find the total surface area of the cuboid.
A room is 22m long, 15m broad and 6m high. Find the area of its four walls and the cost of painting including doors and windows at the rate of Rs.12per m2.
The dimensions of a cuboidal box are 6 m × 400 cm × 1.5 m. Find the cost of painting its entire outer surface at the rate of ₹ 22 per m2.
