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Question
A conical flask is full of water. The flask has base radius r and height h. The water is poured into a cylindrical flask of base-radius mr. Find the height of water in the cylindrical flask.
Solution
Given base radius of conical flask be r
Height of conical flask is h
Volume of cone = `1/3pir^2h`
So its volume = `1/3pir^2h` ........(1)
Given base radius of cylindrical flask is ms.
Let height of flask be h1
Volume of cylinder =`pir^2h_1`
So its volume =`22/7(mr)^2xxh_1` .........(2)
Since water in conical flask is poured in cylindrical flask their volumes are same
(1) = (2)
⇒`1/3pir^2h = pi(mr)^2xxh_1`
⇒ `h_1 = h/(3m^2)`
∴Height of water in cylindrical flask = `h/(3m^2)`
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