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Question
A solid metallic cuboid of dimensions 9 m × 8 m × 2 m is melted and recast into solid cubes of edge 2 m. Find the number of cubes so formed.
Solution
Volume of cuboid, V1 =\[l \times b \times h\] = \[9 m \times 8 m \times 2 m = 144 m^3\]
Volume of cube, V2=\[a^3 = 2^3 = 8 m^3\]
Number of cubes formed=\[\frac{Volume of Cuboid}{Volume of cube} = \frac{V_1}{V_2} = \frac{144 m^3}{8 m^3} = 18\]
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