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A Solid Metallic Cuboid of Dimensions 9 M × 8 M × 2 M is Melted and Recast into Solid Cubes of Edge 2 M. Find the Number of Cubes So Formed. - Mathematics

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Question

A solid metallic cuboid of dimensions 9 m × 8 m × 2 m is melted and recast into solid cubes of edge 2 m. Find the number of cubes so formed.

Solution

Volume of cuboid, V1 =\[l \times b \times h\] = \[9 m \times 8 m \times 2 m = 144 m^3\]

Volume of cube, V2=\[a^3 = 2^3 = 8 m^3\]

Number of cubes formed=\[\frac{Volume of Cuboid}{Volume of cube} = \frac{V_1}{V_2} = \frac{144 m^3}{8 m^3} = 18\]

Thus, 18 cubes can be formed from the given cuboid.
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2016-2017 (March) Foreign Set 3

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