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A Container in the Shape of a Frustum of a Cone Having Diameters of Its Two Circular Faces as 35 Cm and 30 Cm and Vertical Height 14 Cm, is Completely Filled with Oil. If Each Cm3 of Oil Has - Mathematics

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Question

A container in the shape of a frustum of a cone having diameters of its two circular faces as 35 cm and 30 cm and vertical height 14 cm,
is completely filled with oil. If each cm3 of oil has mass 1.2 g, then find the cost of oil in the container if it costs ₹40 per kg.

Sum

Solution

We have,

Height, h = 14 cm

Rdius of upper end, `"R"=35/2 = 17.5  "cm" and`

Radius of lower end, `r = 30/2 = 15  "cm"` 

Now,

Volume of the container `= 1/3pi"h"("R"^2+"r"^2+"Rr")`

`= 1/3xx22/7xx14xx(17.5^2+15^2+17.5xx15)`

`= 44/3 xx (306.25 + 225 + 262.5)`

`=44/3xx793.75`

`=34925/3  "cm"^3`

So, the mass of the oil that is completely filled in the container`= 34925/3 xx 1.2`

= 13970 Kg

= 13.97 Kg

∴ The cost of the oil in the container = 40 ×1.2

= 13970 Kg

= 13.97

∴ The cost of the oil in the container = 40 × 13.97 = ₹ 558.80

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Chapter 19: Volume and Surface Area of Solids - Exercise 19C [Page 911]

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RS Aggarwal Mathematics [English] Class 10
Chapter 19 Volume and Surface Area of Solids
Exercise 19C | Q 10 | Page 911

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