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Question
A convex lens of focal length 10 cm is placed in contact with a concave lens of focal length 20 cm. The focal length of this combination of lenses will be:
(a) +10 cm
(b) +20 cm
(c) −10 cm
(d) −20 cm
Solution
+20 cm
We know that:
Power (P) = `1/"focal length"`
Therefore
Power of convex lens `p_1=1/(10cm)=1/(0.1m)=+10D`
Power of convave lens `P_2=1/(-20cm)=-1/(0.2m)=-5D`
We know that power of lens adds up when lenses comes in contact. Therefore, we have:
Net power (P) = P1 + P2
Net power (P) = 10 D-5 D = 5 D
Net focal length = `1/"power"=1/5=0.2m=20cm`
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