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Question
A cylindrical glass with diameter 20 cm has water to a height of 9 cm. A small cylindrical metal of radius 5 cm and height 4 cm is immersed it completely. Calculate the raise of the water in the glass?
Solution
Radius of the cylindrical glass (r) = 10 cm
Height of the water (h) = 9 cm
Radius of the cylindrical metal (R) = 5 cm
Height of the metal (H) = 4 cm
Let the height of the water raised be h
Volume of the water raised in the cylinder = Volume of the cylindrical metal
πr2h = πr2H
π × 102 × h = π × 52 × 4
h = `100/100`
h = 1 cm
∴ The height of the raised water in the glass = 1 cm.
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