Question

A dice is thrown once. What is the probability of getting a number less than or equal to 2?  

Answer 1

Number of possible outcomes when dice is thrown = {1, 2, 3, 4, 5, 6} 

n(S) = 6 

Event of getting a number less than or equal to 2 = E = {1, 2}

n(E) = 2 

Probability of getting a number less than or equal to 2 = ${\displaystyle \frac{n\left(E\right)}{n\left(S\right)}=\frac{2}{6}=\frac{1}{3}}$