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Question
Nine cards (identical in all respects) are numbered 2 to 10. A card is selected from them at random. Find the probability that the card selected will be a multiple of 3.
Solution
There are 9 cards from which one card is drawn.
Total number of elementary events = n(S) = 9
From numbers 2 to 10, there are 3 numbers which are multiples of 3 i.e. 3, 6, 9
Favorable number of events = n(E) = 3
Probability of selecting a card with a multiple of 3 = `(n(E))/(n(S)) = 3/9 = 1/3`
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