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Question
A ball is drawn at random from a box containing 12 white, 16 red and 20 green balls. Determine the probability that the ball drawn is red or white.
Solution
Total number of balls in the box = 48
Total possible outcomes on drawing a ball = 48
n(S) = 48
red or a white ball = 12 + 16 = 28 balls
Event of drawing a red or white ball = E = 28
n(E) = 28
Probability of not drawing a green ball = `(n(E))/(n(S)) = 28/48 = 7/12`
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Solution:
Suppose ‘S’ is sample space.
∴ n(S) = 52
Event A: Card drawn is a red card.
∴ Total red cards = `square` hearts + 13 diamonds
∴ n(A) = `square`
∴ p(A) = `square/("n"("s"))` ....formula
∴ p(A) = `26/52`
∴ p(A) = `square`