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Question
Thirty identical cards are marked with numbers 1 to 30. If one card is drawn at random, find the probability that it is a multiple of 4 or 6.
Solution
There are 30 cards from which one card is drawn.
Total number of elementary events = n(S) = 30
From numbers 1 to 30, there are 10 numbers which are multiple of 4 or 6 i.e. {4, 6, 8, 12, 16, 18, 20, 24, 28, 30}
Favorable number of events = n(E) = 10
Probability of selecting a card with a multiple of 4 or 6 = `(n(E))/(n(S)) = 10/30 = 1/3`
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A card is drawn from a well-shuffled pack of 52 playing cards. Find the probability of the event, the card drawn is a red card.
Solution:
Suppose ‘S’ is sample space.
∴ n(S) = 52
Event A: Card drawn is a red card.
∴ Total red cards = `square` hearts + 13 diamonds
∴ n(A) = `square`
∴ p(A) = `square/("n"("s"))` ....formula
∴ p(A) = `26/52`
∴ p(A) = `square`
