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Question
A ball is drawn at random from a box containing 12 white, 16 red and 20 green balls. Determine the probability that the ball drawn is not green.
Solution
Total number of balls in the box = 48
Total possible outcomes on drawing a ball = 48
n(S) = 48
Event of drawing a green ball = E = 2
n(E) = 20
Probability of drawing a green ball = `(n(E))/(n(S)) = 20/48 = 5/12`
Probability of not drawing a green ball = `1 - 5/12 = (12 - 5)/12 = 7/12`
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