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A Father is Three Times as Old as His Son. in 12 Years Time, He Will Be Twice as Old as His Son. Find the Present Ages of Father and the Son. - Mathematics

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Question

Father's age is three times the sum of age of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

Definition

Solution

Let the present age of father be x years and the present age of his son be years.

The present age of father is three times the age of the son. Thus, we have

`x= 3y`

`⇒ x - 3y =0`

After 12 years, father’s age will be (x + 12) years and son’s age will be (y + 12) years. Thus using the given information, we have

`x+ 12 = 2(y+12)`

`⇒ x + 12 = 2y +24`

`⇒ x - 2y -12 =0`

So, we have two equations

`x- 3y =0`

`x-2y -12=0`

Here x and y are unknowns. We have to solve the above equations for x and y.

By using cross-multiplication, we have

`x/((-3)xx(-12)-(-2)xx0)=(-y)/((1xx(-12)-1xx0))=1/((1xx(-2)-1xx(-3)))`

`⇒ x/(36-0)=(-y)/(-12-0)=1/(-2+3)`

`⇒ x/(36)= (-y)/-12=1/1`

`⇒ x/36=y/12=1`

`⇒ x = 36, y=12`

Hence, the present age of father is 36 years and the present age of son is 12 years.

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Chapter 3: Pair of Linear Equations in Two Variables - Exercise 3.9 [Page 92]

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RD Sharma Mathematics [English] Class 10
Chapter 3 Pair of Linear Equations in Two Variables
Exercise 3.9 | Q 7 | Page 92

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