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Question
Father's age is three times the sum of age of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.
Solution
Let the present age of father be x years and the present age of his son be y years.
The present age of father is three times the age of the son. Thus, we have
`x= 3y`
`⇒ x - 3y =0`
After 12 years, father’s age will be (x + 12) years and son’s age will be (y + 12) years. Thus using the given information, we have
`x+ 12 = 2(y+12)`
`⇒ x + 12 = 2y +24`
`⇒ x - 2y -12 =0`
So, we have two equations
`x- 3y =0`
`x-2y -12=0`
Here x and y are unknowns. We have to solve the above equations for x and y.
By using cross-multiplication, we have
`x/((-3)xx(-12)-(-2)xx0)=(-y)/((1xx(-12)-1xx0))=1/((1xx(-2)-1xx(-3)))`
`⇒ x/(36-0)=(-y)/(-12-0)=1/(-2+3)`
`⇒ x/(36)= (-y)/-12=1/1`
`⇒ x/36=y/12=1`
`⇒ x = 36, y=12`
Hence, the present age of father is 36 years and the present age of son is 12 years.
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