Advertisements
Advertisements
Question
A faulty balance of equal arms but pans of unequal weight is used to find the weight of a body. By the method of double weighing the weights are found as 8 kg and 8.2 kg. Find the actual weight of the body.
Solution
m0= actual weight
mL = weight of leftpan
mR = weight of right pan
mL + 8 = m0 + mR
mR + 8.2 kg = m0 + m2
adding the two equations
mL + mR + 16.2kg = 2m0 + m2 +mR
⇒ 16.2 = 2m0
m0 = 8.1 kg
APPEARS IN
RELATED QUESTIONS
A faulty balance of unequal arms and pans of unequal weights is used to find the true weight of a metal. By double weighing the weights are found to be 1210 g and 1000 g. Calculate the true weight of the metal.
In figure, a uniform bar of length l m is supported at its ends and loaded by a weight W kgf at its middle. In equilibrium, find the reactions R1 and R2 at the ends.
`["Hint:" "In equilibrium" "R"_1 + "R"_2 = "W" "and" "R"_1 xx l/2 = "R"_2 xx l/2]`
State two conditions when the work done by a force acting on a body is zero.
What is meant by equilibrium and state the conditions of equilibrium of a body?
A boy of mass 30 kg is fitting at a distance of 2 m from the middle of a see-saw. Where should a boy of mass 40 kg sit so as to balance the see-saw?
A ball is placed on a compressed spring. When the spring is released, the ball is observed to fly away.
(i) What form of energy does the compressed spring possess?
(ii) Why does the ball fly away?
Give an experiment to verify the principle of moments.
A non uniform beam of weight 120 N pivoted at one end is shown in the diagram below. Calculate the value of F to keep the beam in equilibrium.
