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Question
A force of 50N acts on the object of mass of 20 kg. shown in the figure. Calculate the acceleration of the object in x and y directions.
Solution
Given F = 50 N and m = 20 kg
(1) component of force along x – direction
Fx = F cos θ
= 50 × cos 30° = 43.30 N
ax = `F_x/m` = `43.30/20` =2.165 ms-2
(2) Component of force along y – direction
Fy = F sin θ = 50 sin 30° = 25 N
ay = `F_y/m` = `25/20` = 1.25 ms-2
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