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Question
A game consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12; as shown below.
If the outcomes are equally likely, find the probability that the pointer will point at:
- 6
- an even number.
- a prime number.
- a number greater than 8.
- a number less than or equal to 9.
- a number between 3 and 11.
Solution
Total number of possible outcomes = 12
i. Number of favorable outcomes for 6 = 1
P(the pointer will point a 6) = `1/12`
ii. Favorable outcomes for an even number are 2, 4, 6, 8, 10, 12
Number of favorable outcomes = 6
P(the pointer will be at an even number) = `6/12 = 1/2`
iii. Favorable outcomes for a prime number are 2, 3, 5, 7, 11
Number of favorable outcomes = 5
P(the pointer will be at a prime number) = `5/12`
iv. Favourable outcomes for a number greater than 8 are 9, 10, 11, 12
Number of favorable outcomes = 4
P(the pointer will be at a number greater than 8) = `4/12 = 1/3`
v. Favorable outcomes for a number less than or equal to 9 are 1, 2, 3, 4, 5, 6, 7, 8, 9
Number of favorable outcomes = 9
P(the pointer will be at a number less than or equal to 9) = `9/12 = 3/4`
vi. Favorable outcomes for a number between 3 and 11 are 4, 5, 6, 7, 8, 9, 10
Number of favorable outcomes = 7
P(the pointer will be at a number between 3 and 11) = `7/12`
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