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Question
A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person from the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is
- extremely patient,
- extremely kind or honest.
Which of the above values you prefer more?
Solution
Total number of persons = 12.
Number of persons who are extremely patient = 3.
Number of persons who are extremely honest = 6.
Number of persons who are extremely kind = 12 − 3 − 6 = 3.
i. P(selecting a person who is extremely patient) = `("Number of favourable outcomes")/"Number of all possible outcomes"`
`= 3/12 = 1/4`
Thus, the probability of selecting a person who is extremely patient is `1/4`.
ii. P(selecting a person who is extremely kind or honest) =`("Number of favourable outcomes")/"Number of all possible outcomes"`
`= 6+3/12 = 9/12= 3/4 `
Thus, the probability of selecting a person who is extremely kind or honest is `3/4`.
From the three given values, we prefer honesty more.
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