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Question
A group consists of 12 persons, of which 3 are extremely patient, other 6 are extremely honest and rest are extremely kind. A person form the group is selected at random. Assuming that each person is equally likely to be selected, find the probability of selecting a person who is extremely patient
Solution
Number of persons in the group = 12
∴ Total number of outcomes = 12
Number of persons who are extremely patient = 3
So, the favourable number of outcomes are 3.
∴ P(selecting a person who is extremely patient) =\[\frac{\text{ Favourable number of outcomes }}{\text{ Total number of outcomes }} = \frac{3}{12} = \frac{1}{4}\]
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