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Question
A heavy nucleus P of mass number 240 and binding energy of 7.6 MeV per nucleon splits into two nuclei Q and R of mass number 110 and 130 and binding energy per nucleon of 8.5 MeV and 8.4 MeV respectively. Calculate the energy released in fission.
Solution
The nuclear reaction,
\[\ce{P^240 -> Q^110 + R^130 + Q}\]
As per the given data energy released in the fission,
Q = 110 × 8.5 + 130 × 8.4 - 240 × 7.6
Q = 203 MeV
Hence, it is the energy released in the fission.
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