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Question
Calculate the binding energy of an alpha particle in MeV. Given
mass of a proton = 1.007825 u
mass of a neutron = 1.008665 u
mass of He nucleus = 4.002800 u
1u = 931 MeV/c2
Solution
Given:
mp = 1.007825 u
mn = 1.008665 u
mα = 4.002800 u
B.E. = Δmc2
= `{(2m_p + 2m_n) - m_alpha}c^2`
= `{(2 xx 1.007825 + 2 xx 1.008665) - 4.002800} xx c^2`
B.E. = `0.03018 xx 931` MeV
B.E. = 28.09758 MeV
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