Advertisements
Advertisements
प्रश्न
Calculate the binding energy of an alpha particle in MeV. Given
mass of a proton = 1.007825 u
mass of a neutron = 1.008665 u
mass of He nucleus = 4.002800 u
1u = 931 MeV/c2
उत्तर
Given:
mp = 1.007825 u
mn = 1.008665 u
mα = 4.002800 u
B.E. = Δmc2
= `{(2m_p + 2m_n) - m_alpha}c^2`
= `{(2 xx 1.007825 + 2 xx 1.008665) - 4.002800} xx c^2`
B.E. = `0.03018 xx 931` MeV
B.E. = 28.09758 MeV
APPEARS IN
संबंधित प्रश्न
Obtain the binding energy (in MeV) of a nitrogen nucleus `(""_7^14"N")`, given `"m"(""_7^14"N")` = 14.00307 u.
The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei `""_20^41"Ca"` and `""_13^27 "Al"` from the following data:
`"m"(""_20^40"Ca")` = 39.962591 u
`"m"(""_20^41"Ca")` = 40.962278 u
`"m"(""_13^26"Al")` = 25.986895 u
`"m"(""_13^27"Al")` = 26.981541 u
What characteristic property of nuclear force explains the constancy of binding energy per nucleon (BE/A) in the range of mass number ‘A’ lying 30 < A < 170?
If the nucleons of a nucleus are separated from each other, the total mass is increased. Where does this mass come from?
Answer the following question.
Draw the curve showing the variation of binding energy per nucleon with the mass number of nuclei. Using it explains the fusion of nuclei lying on the ascending part and fission of nuclei lying on the descending part of this curve.
An electron in hydrogen atom stays in its second orbit for 10−8 s. How many revolutions will it make around the nucleus at that time?
The difference in mass of a nucleus and its constituents is called ______.
A body's centre of mass
Tritium is an isotope of hydrogen whose nucleus Triton contains 2 neutrons and 1 proton. Free neutrons decay into `p + bare + barν`. If one of the neutrons in Triton decays, it would transform into He3 nucleus. This does not happen. This is because ______.
Heavy stable nucle have more neutrons than protons. This is because of the fact that ______.
