मराठी

Draw the Curve Showing the Variation of Binding Energy per Nucleon with the Mass Number of Nuclei. Using It Explain the Fusion of Nuclei Lying on Ascending Part and Fission - Physics

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प्रश्न

Answer the following question.
Draw the curve showing the variation of binding energy per nucleon with the mass number of nuclei. Using it explains the fusion of nuclei lying on the ascending part and fission of nuclei lying on the descending part of this curve.

टीपा लिहा

उत्तर


The above curve tells us that the binding energy per nucleon is smaller for heavier nuclei as well as for lighter nuclei than for the middle order nuclei (with mass number lying between 30 to 170). Meaning heavier nuclei are less stable thus they undergo fission and lighter nuclei undergo fusion in order to form the nucleus lying in the range of the mass number 30 to 170. 

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2019-2020 (February) Delhi (Set 2)

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संबंधित प्रश्‍न

Consider the fission of `""_92^238"U"` by fast neutrons. In one fission event, no neutrons are emitted and the final end products, after the beta decay of the primary fragments, are `""_58^140"Ce"` and `""_44^99"Ru"`. Calculate Q for this fission process. The relevant atomic and particle masses are

`"m"(""_92^238"U")` = 238.05079 u

`"m"(""_58^140"Ce")` = 139.90543 u

`"m"(""_44^99"Ru")` = 98.90594 u


In which of the following decays the atomic number decreases?

(a) α-decay
(b) β+-decay
(c) β-decay
(d) γ-decay


Find the binding energy per nucleon of `""_79^197"Au"` if its atomic mass is 196.96 u.

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)


In a nuclear reactor, what is the function of:
(i) The moderator
(ii) The control rods
(iii) The coolant


A body's centre of mass


Nuclei with magic no. of proton Z = 2, 8, 20, 28, 50, 52 and magic no. of neutrons N = 2, 8, 20, 28, 50, 82 and 126 are found to be very stable.

(i) Verify this by calculating the proton separation energy Sp for 120Sn (Z = 50) and 121Sb = (Z = 51).

The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by `S_P = (M_(z-1^' N) + M_H - M_(ZN))c^2`. 

Given 119In = 118.9058u, 120Sn = 119.902199u, 121Sb = 120.903824u, 1H = 1.0078252u.

(ii) What does the existance of magic number indicate?


Calculate the binding energy of an alpha particle in MeV. Given

mass of a proton = 1.007825 u

mass of a neutron = 1.008665 u

mass of He nucleus = 4.002800 u

1u = 931 MeV/c2


Define binding energy per nucleon.


State the significance of binding energy per nucleon.


What is meant by “binding energy per nucleon” of a nucleus?


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