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Question
A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.
`["Assume "pi=22/7]`
Solution
Inner radius (r1) of hemispherical tank = 1 m
Thickness of hemispherical tank = 1 cm = 0.01 m
Outer radius (r2) of hemispherical tank = (1 + 0.01) m = 1.01 m
The volume of iron used to make such a tank = `2/3pi (r_2^3-r_1^3)`
= `[2/3xx22/7xx{(1.01)^3-(1)^3}]m^3`
= `[44/21xx(1.030301-1)]m^3`
= 0.06348 m3 (approximately)
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