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Question
A housing society consisting of 5,500 people needs 100 L of water per person per day. The cylindrical supply tank is 7 m high and has a diameter 10 m. For how many days will the water in the tank last for the society?
Solution
Total number of people = 5500
Water required per person per day = 100 L
Total requirement of water by 5500 peoples = 100 × 5500 = 550000 L
Height of the cylindrical tank = 7 m
Diameter of the cylindrical tank = 10 m
∴ Radius = 5 m ...`[∵ ("Diameter")/2 = "Radius"]`
∴ Volume of cylinder = πr2h
= `22/7 xx 5 xx 5 xx 7`
= 22 × 25
= 550 m3
= 550 × 1000 ...[∵ 1 m3 = 1000 L]
= 550000 L
Hence, for 1 day the water in the tank lost for the society and in one day society needs 550000 L of water.
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