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Question
From a solid right circular cylinder with height 10 cm and radius of the base 6 cm, a right circular cone of the same height and same base is removed. Find the volume of the remaining solid.
Solution
Given, Height of the cylinder (h) = 10 cm
And radius of the base (r) = 6 cm
∴ Volume of the cylinder = πr2h
Height of the cone = 10 cm
And radius of the base of cone = 6 cm
∴ Volume of the cone = `1/3pir^2h`
∴ Volume of the remaining part
= `pir^2h - 1/3pir^2h`
= `2/3pir^2h`
= `2/3 xx 22/7 xx 6 xx 6 xx 10 cm^3`
= `44/21 xx 360`
= `(44 xx 120)/7 cm^3`
= `5280/7`
= `754 2/7 cm^3`
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