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Question
A soft drink is available in two packs − (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?
`["Assume "pi=22/7]`
Solution
The tin can will be cuboidal in shape while the plastic cylinder will be cylindrical in shape.
Length (l) of tin can = 5 cm
Breadth (b) of tin can = 4 cm
Height (h) of tin can = 15 cm
Capacity of tin can = l × b × h
= (5 × 4 × 15) cm3
= 300 cm3
Radius (r) of circular end of plastic cylinder = (7/2)cm = 3.5 cm
Height (H) of plastic cylinder = 10 cm
Capacity of plastic cylinder = πr2H
`=[22/7xx(3.5)^2xx10]cm^3`
= (11 x 35) cm3
= 385 cm3
Therefore, plastic cylinder has the greater capacity.
Difference in capacity = (385 − 300) cm3 = 85 cm3
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